What is the Specific heat of the Unknown metal?
Q. When a piece of unknown metal weighing 44.1 grams, and at a temperature of 99.0 degrees C is placed in a calorimeter containing 86.1 grams of water at 20.6 degrees C, the temperature increases to 22.3 degrees C. The specific het of water is 4.18 J/gram and the heat capacity of the calorimeter is 247 J/K, what is the specific heat of the unknown metal?
Asked by Jenny K - Tue Oct 31 12:00:19 2006 - - 1 Answers - 1 Comments

A. Specific heat often has units of heat/(mass x temperature change) SH = J/g*C . Changes in temperature on the Kelvin scale and the Celsius scale are the same and need no conversion. In your problem, the mass is 44.1 g, the temperature change is (99.0 - 22.3) C and the total heat measured needs to be calculated from the heat change of the water and the calorimeter. The water's SH is 4.18 J/g*C (4.18 J/g*K is the same), and you have stated there is 86.1 g of water that rose from 20.6 C to 22.3 C. The total heat gained by the water is then 4.18 J/g*C X 86.1 g X 1.7 C. (= Hw) The heat gained by the calorimeter is 247 J/K, and since it was in equilibrium with the cold water, we will use the same change as for the water, 1.7 C. Again,… [cont.]
Answered by questor_2001 - Tue Oct 31 12:42:46 2006

How to determine the specific heat capacity of a metal?
Q. A 20.0-g sample of an unknown metal is heated to 96.0 C and is placed in a insulated container containing 126 g of water at a temperature of 20.4 C. After the metal cools, the final temperature of the metal and water is 23.2 C. Calculate the specific heat capacity of the metal, assuming that no heat escapes to the surroundings.
Asked by LyTasha - Sat Nov 6 11:24:23 2010 - - 1 Answers - 0 Comments

A. heat lost by the metal = heat gained by the water mCdT metal = m C dT water (20.0 grams)(C)(72.8 drop in temp) = (126 g)(4.184 J/g-C)(2.8 rise in temp) 1456 (C) = 1476 Joules C of the metal = 1.01 J/g-C
Answered by Steve O - Sat Nov 6 12:41:28 2010

What is the difference between specific heat and temperature?
Q. I know that Kelvin measures specific heat, while Celsius and Farenheit measure temperature, but what is the actual difference?
Asked by ... - Fri Aug 28 11:48:40 2009 - - 1 Answers - 0 Comments

A. Kelvin Celsius and Fahrenheit mesure temperature The specific heat of a given substance is the amount of heat (energy) it can store per unit of mass at a given temoerature
Answered by santmann2002 - Fri Aug 28 11:56:29 2009

What is the relationship between a metal's specific heat and its ability to conduct heat / electricity?
Q. What is the relationship between a metal's specific heat (heat capacity) and its ability to conduct heat or its ability to conduct electricity? What metals would be best suited for cooking utensils and why?
Asked by catalyst_infinity - Sun Mar 8 19:27:22 2009 - - 1 Answers - 0 Comments

A. The higher the specific heat capacity the better the ability to conduct heat. Not sure about the relationship between s.h.c. and electrical conduction though.Metals with low specific heat capacity, such as silver, would be best suited for cooking utensils as the do not require much input to reach the desired temperature.
Answered by Kay - Sun Mar 8 19:37:20 2009

How do you determine specific heat in this problem?
Q. A 0.350 kg piece of metal at 100 degrees celsius is dropped into a 0.100 kg aluminum cup containing 0.5 kg of water at 15 degrees celsius. The final temperature of the system is 40 degrees celsius. What is the specific heat of the metal, assuming no heat is exchanged with the surroundings? The specific heat of aluminum is 900 J/kg*C, and the specific heat of water is 4186 J/kg*C.
Asked by jackmanesch - Tue May 5 17:53:50 2009 - - 1 Answers - 1 Comments

A. First find the specific heat c of the Al+H2O: m3 = m1+m2 = 0.6 kg c3 = (m1c1+m2c2)/m3 = 3638.333 J/kg-K Now we reassign the roles of materials 1, 2 and 3. Mix part 1 (the metal at T1 = 100 C) with part 2 (the Al+H2O at T2 = 15 C with c2 = 3638.333 J/kg-K) and solve for c1 when T3 = 40 C. Basic equation is c1m1(T3-T1) = -c2m2(T3-T2) c1 = -c2m2(T3-T2)/(m1(T3-T1)) = 2598.81 J/kg-C (answer)
Answered by kirchwey - Wed May 6 21:37:02 2009

How do you find the specific heat of the metal in the following problem?
Q. A 0.350 kg piece of metal at 100 C is dropped into a 0.100 kg aluminum cup containing 0.500 kg of water at 15 C. The final temperature of the system is 40 C. What is the specific heat of the metal, assuming no heat is exchanged with the surroundings? The specific heat of aluminum is 900 J/kg C, and the specific heat of water is 4186 J/kg C.
Asked by Alice Ling - Mon Jul 19 16:11:08 2010 - - 2 Answers - 0 Comments

A. Heat came out of the metal and went into the water and the aluminum m_metal * c_metal * deltaT_metal = m_water * c_water * deltaT_water + m_cup * c_cup * deltaT_cup where m_metal, m_water, m_cup are the mass of the metal, the water, and the cup c_metal, c_water, c_cup are the specific heat of the metal, the water and the cup deltaT_metal, deltaT_water and deltaT_cup are the temperature changes in degrees C of the metal, the water and the cup. Everything is known here except c_metal. Just put in all the numbers. You will have an equation of the form (number) x c_metal = (another number).
Answered by Randy P - Mon Jul 19 16:31:39 2010

Specific heat?
Q. I need help for solving specific heat for my upcoming exam. How can i compute the specific heat? Is there an easy technique? if there is, please tell me how? Sample problem: A thermos bottle contains 80g of water at 15 degree celcius. Into this placed 40g of metal at 85 degree celcius after equilibrium is established, the temparature of the water and metal is 35 degree celcius. What is the specific heat of metal? Assume no heat loss to the thermos bottle? (if there is an answer of (3400gdegree celcius - (subtract) 1400g degree celcius) where do 1400g degree celcius comes from?
Asked by Jeniv the Brit - Fri Feb 23 21:03:11 2007 - - 1 Answers - 0 Comments

A. Key is to say "heat lost by hot" = "heat gained by cold" (ms(Tinitial - Tfinal)) for hot = ms(Tfinal - Tinitial) for cold 80(1)(35-15) = 40(s)(85 -35) solve for s in cal/gdegC Don't understand last bit
Answered by hello - Fri Feb 23 21:15:39 2007

What is the specific heat of the lead pellet?
Q. A lead pellet having a mass of 26.47 grams at 89.98 degrees C is dropped into 100.0 grams of water in an insulated container. The water temperature rose from 22.50 degrees C to 23.17 degrees C. What is the specific heat of the lead pellet?
Asked by Sarah - Sat Oct 30 22:18:38 2010 - - 1 Answers - 0 Comments

A. In order to do this question you need this main formula Q=mC T, q1+q2+q3 .=0 m=mass, C=Heat Capacity and T is change in temperature (26.47)(x)(89.98-23.17)+ (100)(4.187)(23.17-22.50) =0 Solve for x which will be specific heat capacity of the pellet of lead x= -(100)(4.187)(23.17-22.50 )/ (26.47)(89.98-23.17) x= -280.529/1768.4607 specific heat capacity cannot be negative x=.1586J/g C hope this helps!
Answered by Adeel Nawaz - Sat Oct 30 23:11:38 2010

Does the specific heat capacity of water change when measured in a different temperature range?
Q. In an experiment I heated water with 3 initial and final temperatures. By solving the equation Q=mc T for c and plugging in the values I got an average specific heat capacity of about 2287J/Kg*K. The actual specific heat capacity of water found in every source is 4190 J/Kg*K. Is the specific heat capacity of water dependent on the range of temperature measured at? If yes, how does the specific heat capacity change?
Asked by Philippmikio - Tue Mar 18 16:03:25 2008 - - 1 Answers - 0 Comments

A. Yes, the specific heat capacities of substances comprising molecules like water are not fixed constants and will vary somewhat depending on its temperature. Accordingly, the temperature at which the measurement is made is usually also specified. Examples of two common ways to cite the specific heat of water are as follows: Water (liquid): cp = 4.1855 J g 1 K 1 (15 C), and Water (liquid): CvH = 74.539 J mol 1 K 1 (25 C)
Answered by PhysicsDude - Sat Mar 22 03:44:52 2008

What is the specific heat capacity for water saturated iron filings?
Q. The specific heat capacity of iron is generally cited at 0.107 cal/gm/deg C, but what about saturated iron filings? The disticntion may be important for the following problem: If I send a 95 liter slug of 47 degree C water through 2 meters of saturated iron filings (say 1 meter deep by 3 meters wide) at a temperature of 12.5 degrees C, will the heat pulse due to conduction get there before the convective heat pulse? Thanks
Asked by Royce Merkin;) - Wed May 14 19:20:53 2008 - - 1 Answers - 0 Comments

A. You need a packing fraction for any serious attempt to solve the first question. For the 2nd question, the heat pulse due to convection will pass through before any conductive heat pulse unless you have solid iron through which the water cannot pass.
Answered by Helmut - Fri May 16 00:23:54 2008

Do you know how to find the specific heat of a calorimetry problem?
Q. For example with this proble: What is the specific heat of nickel if the temperature of a 32.2g sample of nickel is increased by 3.5 degrees celcius when 50. J of heat is added. The answer is .44J/g degrees celcius, but I don't know how they got it (steps, procedures). Does it have anything to do with the way to calculate q sur?
Asked by hellokid - Sat Mar 4 02:48:38 2006 - - 1 Answers - 0 Comments

A. 50j/3.5 deg C= (14.29J/deg C) /32.2g=.44J/deg C grams
Answered by smile no. 817 - Sat Mar 4 03:14:54 2006

What happens to the intermolecular attraction forces in specific heat?
Q. I read in my book that in latent heat, the "heat is used up in changing the state by overcoming the forces of attraction between the particles". So then what happens to the forces in specific heat? Shouldn't they also be decreasing since KE increases on increasing the temp. and that means that the forces must be decreasing. But in that case, what's the difference between those two. PS : I know what's the basic difference, I just wanted to know the difference in reference to my question... Thanks!
Asked by Sammy - Sam - Fri Nov 26 09:02:48 2010 - - 1 Answers - 0 Comments

A. There's not any difference in reference to your questions vs. reality.
Answered by Atheist Slayer - Mon Nov 29 18:33:29 2010

How do you find specific heat and heat capacity?
Q. If 2400 J of heat are added to a 190 g object, its temperature increases by 13 degrees C . *What is the heat capacity of this object? *What is the object's specific heat?
Asked by Katsuma - Wed Jul 14 13:11:01 2010 - - 3 Answers - 0 Comments

A. Q=M x Cp x (T2-T1) Therefore Cp = 2400/(190 x 13) = 0.97 (Object specific heat) The heat capacity is 0.97 x 190 = 184.3 J/K
Answered by Chappy - Wed Jul 14 13:24:32 2010

What are some reasons the specific heat of a mixture be lower than the specific heat of pure water?
Q. for a chemistry lab, the specific heat of our mixture is lower than the specific heat of water. in one experiment, Magnesium oxide was added to HCl and in another experiment plain magnesium was added to HCl. So what would be a reason as to why the specific heat of these mixtures is lower than the specific heat of pure water?
Asked by cat sta - Wed Nov 3 12:18:56 2010 - - 2 Answers - 0 Comments

A. When you add heat to water, a lot of that energy goes into breaking the intermolecular hydrogen bonds instead of warming the solution. Dissolved chemicals interfere with water's ability to form hydrogen bonds, so a less energy is soaked up by breaking them and it takes less to warm the solution.
Answered by Trouztrouz - Wed Nov 3 12:33:25 2010

What is the specific heat capacity of the alloy?
Q. A 10.25 grams sample of metal alloy is heated to 99.10 C and then is dropped into 20.0 g of water in a calorimeter at 18.53 C. If the water temperature increases to 22.03 C, what is the specific heat capacity of the alloy? The specific heat capacity for water is 4.184 J/ gC.
Asked by hawksup2 - Sun Dec 14 22:49:17 2008 - - 1 Answers - 0 Comments

A. -q(alloy)=q(water) -(10.25)(c alloy)(22.03 - 99.10) = (20)(4.184)(22.03-18.53) c alloy = (20)(4.184)(22.03-18.53) / -(10.25)(22.03 - 99.10) c alloy = 0.371 J/g C
Answered by camarcucci - Sun Dec 14 23:09:35 2008

Why is the specific heat of solid water less than that of liquid water?
Q. I understand the hydrogen bond in water is very strong making it's specific heat in the liquid state very high, but why is the specific heat of ice so much less?
Asked by Green Jeans - Sun Dec 9 21:06:02 2007 - - 1 Answers - 0 Comments

A. what happens when you heat ice? it turns to water. What happens when you heat water? it turns to vapor. Think about it like this. The quantity for delta fusion is much lower than the heat of vaporization. Meaning that the liquid water has the potential to hold much more heat than does ice. The molecules can move around more freely in water than in ice. This allows them to accompany the heat much better than ice
Answered by cahstick - Sun Dec 9 21:15:05 2007

What is the specific heat capacity of the mineral?
Q. A geologist is trying to identify an unknown mineral by measuring its specific heat capacity. A 307g sample of the mineral was heated to 98.7C and placed into a calorimeter containing 72.4 g of water at 23.6C. The heat capacity of the calorimeter was 15.7 J/K. The final temperature in the calorimeter was 32.4C. What is the specific heat capacity of the mineral? Thanks for the help!
Asked by REDSIX - Sun Mar 15 00:24:59 2009 - - 3 Answers - 0 Comments

A. MCT = MCT Heat loss = heat gained 307 * C * (98.7-32.4) = 72.4* 4.2* (32.4-23.6) [ Assuming no heat loss to the container or environment] C= 2675.904 / 307 * (98.7-32.4) = 2675.904 / 20354.1 = 0.13 j/g degree C
Answered by Monah - Sun Mar 15 00:43:06 2009

How does specific heat relate to the materials ability to transfer heat?
Q. like water (4.18) has a higher specific heat, so why does a metal (for example iron- 0.449) transfer heat better?
Asked by Talk.wit.yo.hipss. - Thu Mar 19 16:56:39 2009 - - 2 Answers - 0 Comments

A. First, consider the formula determining the required amount of heat energy to change the temperature of an object. Q = mc~t Where Q = to the heat energy required, m is the mass, c is the specific heat and ~ (used in place of delta) t is the change in temperature. Lets assume the mass is 1 kg. 4180 is the specific heat of water. To raise it 10 degrees would require 41800 joules of energy. Conversely, it would release 41800 joules of energy when cooling down. Now lets go with iron. Again, 1 kg and 449 specific heat. 10 degrees. Q = 1*449*10 = 4490 joules. What this means is that iron requires less heat to heat up, and releases less when it cools down. It isnt that it transfers heat [better] but it does so with less energy required to… [cont.]
Answered by Jerry M - Thu Mar 19 17:11:03 2009

what is the relation between specific heat of a substance and atomic mass?
Q. I have some questions which concern the specific heat of a metal and we have to find the atomic mass. How do we do it?
Asked by Amy - Mon Oct 8 06:58:35 2007 - - 3 Answers - 0 Comments

A. Dulong and Petit from their researches upon the elements concluded that the ultimate atoms of all elements possessed the same capacity for heat and they accordingly announced the law that : " The specific heat of elementary substances is in their inverse ratio to their atomic weights." the relation between the specific heat and atomic weight of compounds is expressed by Regnault in the following Law : " In all compound bodies containing the same number of atoms and of similar chemical constitution ,the specific heats are in inverse ratio to their atomic weights. "
Answered by sb - Wed Oct 10 04:09:59 2007

Finding specific heat when given heat capacity and mass of substance?
Q. A metal that has a mass of 23.4 g has a heat capacity of 6.18 J/Celsius. What is the specific heat of the metal?
Asked by jprobson.bell - Mon Apr 21 20:44:27 2008 - - 1 Answers - 0 Comments

A. The specific heat of a substance is the amount of heat required to raise the temperature of 1 gram of that substance by 1 degrees celcius. Therefore its unit is (J/g. C) To obtain the specific heat; 6.18 J / C / 23.4 = 0.264 J/g. C
Answered by Guray T - Tue Apr 22 16:03:33 2008